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COPPER: Copper has a density of 8.94 g/cm³. An ingot of copper with a mass of 57 kg (125 lb) is drawn into wire with a diameter of 9.50 mm. What length of wire (in meters) can be produced?

[Volume of wire = (Pie) (radius)^2(length)]

1 Answer

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We can start by using the density of copper to find the volume of the ingot:

density = mass/volume

volume = mass/density

volume = 57 kg / 8.94 g/cm³

volume = 6,386.85 cm³

Next, we can use the formula for the volume of a cylinder to find the length of wire that can be produced:

volume of wire = πr²l

where r is the radius of the wire and l is its length.

The radius of the wire is half of the diameter, so:

r = 9.50 mm / 2 = 4.75 mm = 0.475 cm

We need to convert the length of the wire to meters, so we will use the conversion factor 1 m = 100 cm.

volume of wire = π(0.475 cm)²l

l = volume of wire / [π(0.475 cm)²]

l = 6,386.85 cm³ / [π(0.475 cm)²]

l = 6,386.85 cm³ / 2.2416 cm²

l = 2,848.79 cm

l = 28.49 m (rounded to two decimal places)

Therefore, a length of wire of approximately 28.49 meters can be produced from the given ingot of copper.

User Salman Siddiqui
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