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What two factors make up -40 and add to -8

1 Answer

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To find two factors that multiply to -40 and add to -8, we can use a trial and error method or the factoring formula.

Using the factoring formula, which is:

(x + a) (x + b) = x^2 + (a+b)x + ab

where a and b are the factors we're trying to find, and x^2 + (a+b)x + ab is the original quadratic expression.

We know that:

- a + b = -8

- ab = -40

We can solve for a and b by substituting -8 - a for b in the second equation and solving for a:

a * (-8 - a) = -40

-8a - a^2 = -40

a^2 + 8a - 40 = 0

Using the quadratic formula or factoring, we can solve for a:

a = (-8 ± sqrt(8^2 - 4 * 1 * (-40))) / (2 * 1)

a = (-8 ± sqrt(256)) / 2

a = (-8 ± 16) / 2

a = -4 or a = -10

If we substitute these values for a in the equation a + b = -8, we get:

-4 + b = -8 or -10 + b = -8

b = -8 + 4 or b = -8 + 10

b = -4 or b = 2

Therefore, the two factors that make up -40 and add to -8 are -4 and 10 (or 2 and -10).

User Solid Rhino
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