Answer:
39.92 grams
Step-by-step explanation:
1. get molar mass of each element
2. get molar mass of the whole compound
3. multiply 0.25 moles to the molar mass of the whole compound
To calculate the weight of 0.25 mol of Fe2O3, we need to know the molar mass of Fe2O3.
The molar mass of Fe2O3 can be calculated by adding the molar masses of two iron atoms (Fe) and three oxygen atoms (O) as follows:
Molar mass of Fe2O3 = 2 x (molar mass of Fe) + 3 x (molar mass of O)
The molar mass of Fe is 55.845 g/mol, and the molar mass of O is 15.999 g/mol. Substituting these values in the above equation, we get:
Molar mass of Fe2O3 = 2 x 55.845 g/mol + 3 x 15.999 g/mol
Molar mass of Fe2O3 = 159.69 g/mol
Therefore, the weight of 0.25 mol of Fe2O3 can be calculated as:
Weight = number of moles x molar mass
Weight = 0.25 mol x 159.69 g/mol
Weight = 39.92 g
Therefore, 0.25 mol of Fe2O3 weighs approximately 39.92 grams.
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