Question

For what values of c does the quadratic equation x^2-2x+c=0 have no real roots?

Answer 1

C<1

Explanation:

Im pretty sure

Answer 2

c > 1

Explanation:

For a quadratic equation of the form ax^2 + bx + c = 0 to have no real roots, its discriminant (b^2 - 4ac) must be negative.

In the given quadratic equation, a = 1, b = -2, and c = c. So the discriminant is:

b^2 - 4ac = (-2)^2 - 4(1)(c) = 4 - 4c

For the equation to have no real roots, we need:

b^2 - 4ac < 0

4 - 4c < 0

Solving for c, we get:

4c > 4

c > 1

Therefore, for c > 1, the quadratic equation x^2 - 2x + c = 0 has no real roots.