192k views
2 votes
If f(x) is an exponential function where f(-3)=27 and f(0.5)=83, then find the value of f(0), to the nearest hundredth

User Belzebub
by
7.8k points

1 Answer

5 votes

Answer: f(0) ≈ 4.37

Explanation:

We can use the information given to find the base and the equation of the exponential function.

Let the exponential function be of the form f(x) = a*b^x, where a is the initial value of f(0) and b is the base of the exponential function.

From the given information, we have:

f(-3) = 27 = ab^(-3)

f(0.5) = 83 = ab^(0.5)

To eliminate the variable a, we can divide the second equation by the first equation:

f(0.5)/f(-3) = (ab^(0.5))/(ab^(-3))

83/27 = b^(0.5+3)

b^3 = (83/27)^2

b = (83/27)^(2/3)

Substituting this value of b in the first equation, we can solve for a:

27 = a*(83/27)^(-1)

a = 27*(83/27)

Therefore, the equation of the exponential function is f(x) = (83/27)^(2/3)*((83/27)^(-1))^x.

To find f(0), we substitute x = 0 in the above equation:

f(0) = (83/27)^(2/3)*((83/27)^(-1))^0

f(0) = (83/27)^(2/3)

f(0) ≈ 4.37

User Glen Morse
by
8.4k points

No related questions found