Question

Nasim is flying a kite, holding his hands a distance of 2.5 feet above the ground and letting all the kite’s string play out. He measures the angle of elevation from his hand to the kite to be 28 degrees. If the string from the kite to his hand is 105 feet long, how many feet is the kite above the ground? Round your answer to the nearest hundredth of a foot if necessary.

Please help!

Answer 1

The height of Nasim kite above the ground is 51.79 feet

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let h represent the height from Nasim hand to the kite, hence:

sin(28) = h / 105

h = 49.29

Kite height above the ground = 2.5 + 49.29 = 51.79 feet

The height of Nasim kite above the ground is 51.79 feet

Answer 2

Answer: The height of Nasim's kite above the ground is 51.79 feet

Explanation

Let h represent the height from Nasim hand to the kite, hence:

sin(28) = h / 105

h = 49.29

Kite height above the ground = 2.5 + 49.29 = 51.79 feet

The height of Nasim's kite above the ground is 51.79 feet