A large cooler contains the following drinks,
5 Lemonades, let L reprersent Lemonade
9 Sprites, let S reprersent Sprite
7 Cokes, let C represent Coke and
10 Root beers, let R represent Root beer
Total drinks in the cooler is
Total outcome = 31 drinks
The formula of probability is
a) The probability that you get two cans of Sprite is
Hence, the the probability that you get two cans of Sprite is 12/155
b)
The probability that you get two cans of Coke
The probability that you do not get two cans of Coke will be
Hence, the probability that you do not get two cans of Coke is 148/155
c)
The probability that you get two cans of Root beers is
The probability that you get two cans Lemonades is
The probability that you get either two root beers or two lemonades is
Hence, the probability that you get either two root beers or two lemonades is 11/93
d)
After getting both Sprite and Coke you will multiply the probabilities and then multiply them with 2 because you may choose Coke in first try and Sprite in second or the other way around
The probability that you get one can of Coke and one can of Sprite is
Hence, the probability that you get one can of Coke and one can of Sprite is 21/155
e)
Prob of two of each of the cans of drinks (without replacement) are as follow
The probability that you get two drinks of the same type is
Hence, the probability that you get two drinks of the same type is 112/465