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instead of measuring the length of a stick as 3.06 my student measured in length as 2.955 m find the air percent.​

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well, the error is 3.06 - 2.955 = 0.105.

now, if we take 3.06(origin amount) to be the 100%, what's 0.105 off of it in percentage?


\begin{array}{ccll} amount&\%\\ \cline{1-2} 3.06 & 100\\ 0.105& x \end{array} \implies \cfrac{3.06}{0.105}~~=~~\cfrac{100}{x} \\\\\\ 3.06=10.5\implies x=\cfrac{10.5}{3.06}\implies x\approx 3.43

User Shubham Kumar
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