Question

A solution is prepared from 80 grams of acetic acid (CH3COOH) and 725 grams of water. What is the molality of this solution?

Answer 1

Answer: 1.84

Step-by-step explanation:

molality is moles / Kg

convert 80 grams to moles = 80 / 60=1.33 moles

kg=0.725

1.33/0.725 = 1.84 molality acetic acid