At STP (standard temperature and pressure), one mole of any ideal gas occupies a volume of 22.4 liters. Therefore, we can use the following formula to solve the problem:
n1 / V1 = n2 / V2
where n1 and V1 are the number of moles and volume of nitrogen gas at the first condition, and n2 and V2 are the number of moles and volume of nitrogen gas at the second condition.
We know that at STP, 6.5 moles of N2 occupy a volume of 145 liters. Using the formula, we can solve for n2:
n2 = n1 x V2 / V1
n2 = 6.5 x 179 / 145
n2 = 8.02
Therefore, 8.02 moles of N2 occupy a volume of 179 liters at STP. <——————- answer