Question

In the equation below, when the value of d is decreased by 2, how does g change? 4g = 8d + 20

Answer 1

Therefore, when the value of d is decreased by 2, the value of g changes by -3. In other words, g decreases by 3.

Explanation:

We can start by solving the given equation for g:

4g = 8d + 20

g = (8d + 20) / 4

g = 2d + 5

So, we know that g is a function of d and is equal to 2d + 5.

Now, if we decrease the value of d by 2, we get:

d' = d - 2

Substituting this value of d' in the equation for g, we get:

g' = 2d' + 5

g' = 2(d - 2) + 5

g' = 2d - 4 + 5

g' = 2d + 1

Therefore, when the value of d is decreased by 2, the value of g changes by -3. In other words, g decreases by 3.