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5 votes
How much energy does the water in this

experiment absorb according to the
calorimeter data?
Calorimeter Data
Mass (g)
50.0
Specific heat (J/g°C) 4.18
20.5
32.5
T (U/C)
T, (J/g °C)
ано = [ ?] J
Heat Absorbed (J)
Enter

How much energy does the water in this experiment absorb according to the calorimeter-example-1
User Cotton
by
7.3k points

1 Answer

5 votes

Answer:

2508 Joules

Step-by-step explanation:

See the attached worksheet.

The equation for heat transfer is: q = mcΔT,

where q is energy, m is mass, c is the specific heat of the substance, and ΔT is the temperature change (T2 - Ti). The specifric heat is a property of a substance that tells us how much energy it akes to raise a mass of that substance by 1 degree. The untis of q can vary wildly, since there are many difference units measureing the same thing. Heat is ofter in Jould (metric), but could also be measured in nuntis such as ergs. Mass may be grams, kgrams, or other units, Temperatures may be K, C, or even F. All are valid, but the units must all match within the calculation. In this case we are given units of grams, °C, and Joules.

q = mcΔT

q = (50g)*(4.18 J/g°C)*(32.5°C-20.5°C)

q = 2508 J

How much energy does the water in this experiment absorb according to the calorimeter-example-1
User Davidbonachera
by
8.1k points