Answer:
1 lb expensive chocolate
2 lbs other chocolate
Explanation:
let x = number of pounds of the expensive candy bars
let y = number of pounds of the other candy bars
here is the first equation:
(the expensive lbs + other lbs comes to a total of 3 lbs altogether)
x + y = 3
here is the second equation:
($6 per pound + $4.5 per pound = $15)
6x + 4.5y = 15
we can do substitution, elimination, or graph.
let's do elimination with these two equations:
x + y = 3 AND 6x + 4.5y = 15
Let's eliminate the variable x to find variable y, and then use what we found for variable y to find variable x.
Multiply (x + y = 3) with 6
Which looks like this: 6(x+y = 3)
And the above becomes 6x + 6y = 18
the equation x + y = 3 becomes 6x + 6y = 18
the equation 6x + 4.5y = 15 stays the same
Subtract to eliminate x.
6x + 6y = 18
- 6x +4.5y = 15
-------------------------
0 + 1.5y = 3
1.5y = 3, divide both sides by 1.5 to get y
1.5y 3
----- = -----
1.5 1.5
y = 2
Therefore, there are 2 pounds of "other" chocolate in the gift bag. Let's use that to find the pounds of the "expensive" chocolate.
Take one of the original equations and plug in "2" for the variable y.
x + y = 3 OR 6x + 4.5y = 15
Lets use x + y = 3, which becomes x + 2 = 3. Solve that, and you will get:
x = 1
Therefore, there is 1 pound of "expensive" chocolate in the gift bag.
(after you are done solving, plug in the numbers you found to one of the equations...ps i checked already so those are correct.
e.g 1 + 2 = 3 )
:))