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Complete the following sentence: When multiple sources are connected together, their total e.m.f. will be equal to the sum of their individual e.m.fs if they are placed in ______ <, + explanation

User Heymatthew
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Answer:- When they are placed in series.

When multiple emf sources are connected in series then the net or total emf is equal to the sum of their individual emfs .

Say if we have cells of emfs
\epsilon_1 ,
\epsilon_2 ,
\epsilon_3 ,
\epsilon_4 . . . .
\epsilon_n

Then the net emf is ,


\implies \underline{\underline{\green{\epsilon_(net)= \epsilon_1+ \epsilon_2+\dots +\epsilon_n}}}\\

Additional information:-

If the emfs of n cells are equal and they are connected in series then the net emf is given by ,


\implies \epsilon_(net)= n\epsilon \\

where ,


  • \epsilon = emf of a single cell .

Also , when n cells of emfs
\epsilon_1 and
\epsilon_2 . . . . .
\epsilon_n and internal resistances
r_1 ,
r_2 . . . . .
r_n respectively are connected in parallel then the net emf is given by,


\implies \underline{\underline{\green{\epsilon_(net) = \left( (1)/(r_1)+(1)/(r_2)+\dots +(1)/(r_n)\right)^(-1)\left((\epsilon_1)/(r_1)+( \epsilon_2)/(r_2)+\dots +(\epsilon_n)/(r_n)\right)}}}\\

Again suppose if we make a parallel arrangement of cells each having same emf then the net emf remains same that is equal to the emf of individual cell ( Why ? You can try yourself by using the above formula )

and we are done!

User Ricks
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