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Please show work!!!!!!!

Please show work!!!!!!!-example-1
User Intepid
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1 Answer

6 votes

Answer:

J. 56

Explanation:

The picture in this question can be a little deceiving. Each rectangular glass pane is 3 by 10 inches. This means that the picture of the 4 panes overlapping, leaves the center square open. The open area has your inner edges. The question asks for the sum of the inner and outer edges.

Every pane is 10 inches long, so the out perimeter of the figure is 40 inches because the figure has four sides. The rectangles overlap, creating 3 by 3 inch square. 3 inches off either side of a pane leaves 4 inches as the length for the edge of the inner square. Therefore, the perimeter of the inner square is 16 inches.

Outer Perimeter + Inner Perimeter = 40 + 16 = 56 inches

User Rose
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