Question

There are 4,028 cell phones in a box. 1% of them were broken. 50% of the good phones were sold to another city and the remaining were sold locally. What percent of the phones were sold locally? Round to the nearest one percent.

Answer 1

If 1% of the phones were broken, then the number of good phones is 99% of 4,028:

99/100 x 4,028 = 3,987.72 (rounded to 3,988)

Out of the 3,988 good phones, 50% were sold to another city:

50/100 x 3,988 = 1,994

So, the remaining number of good phones that were sold locally is:

3,988 - 1,994 = 1,994

To find the percentage of phones sold locally, we need to divide the number of phones sold locally by the total number of phones:

1,994 / 4,028 = 0.494

Then, we can convert this decimal to a percentage and round to the nearest one percent:

0.494 x 100 ≈ 49%

Therefore, approximately 49% of the phones were sold locally.