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What are the foci of the graph x^2/40-y^2/81=1
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What are the foci of the graph x^2/40-y^2/81=1

User Xavier Delamotte
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7.4k points

2 Answers

6 votes

Answer: y21600x281=1 y 2 1600 - x 2

Step-by-step explanation: for sure chfjjgffjfj ;)

User Michael Berdyshev
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8.1k points
5 votes

Answer:

Explanation:

(y^2)/1600-(x^2)/81=1. y21600−x281=1 y 2 1600 - x 2

User Etov
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7.1k points
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