Answer:
y = (-1/3)x + 2/3
Explanation:
We can use the slope-intercept form of a linear equation to find the equation of the line passing through the points (5, -1) and (2, 2). The slope of a line passing through two points (x1, y1) and (x2, y2) is given by:
slope = (y2 - y1) / (x2 - x1)
Substituting the coordinates of the given points, we have:
slope = (2 - (-1)) / (2 - 5) = -1/3
The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept. We can use the point-slope form of a linear equation to find the y-intercept.
Using the point (5, -1), we have:
-1 = (-1/3)(5) + b
Solving for b, we get:
b = -1 + 5/3 = 2/3
Therefore, the equation of the line passing through the points (5, -1) and (2, 2) is:
y = (-1/3)x + 2/3