Answer:
157 grams magnesium chloride
Step-by-step explanation:
1. We must first find the molar mass (g/mole) of magnesium chloride. The molecular formula is MgCl2.
Add the elemental atromic weights for one molecule of the material:
1 Mg = 24.3
2 Cl = 2*(35.45) = 70.9
Total = 95.2 grams/mole
We can use this as a conversion factor by multiplying it times the moles we are asked to convert: (1.65 moles MgCl2)*(95.2 grams/mole MgCl2).
The moles cancel, leaving us with 157 grams of magnesium chloride.