Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0 Mark this and return

Answer 1

Listed below.

Explanation:

(Let y be the length of the room and x be the width of the room.)

Because the width of the room is 5 feet less than the length of the room, we have:

• x = y - 5.

The area of the room can be solved by multiplying its length and width, so we have x × y or xy = 750.

Substituting x for y - 5 into this equation:

• y (y - 5) = 750.

If we expand the left side of the equation, we get:

• 
  `y^(2)` - 5y = 750

Subtracting 750 from both sides, we get:

• 
  `y^(2)` - 5y - 750 = 0

The equation
`y^(2)` - 5y - 750 = 0 can be factored into:

• (y + 25) (y - 30) = 0

Therefore, 3 equations you can use are:

1. y (y - 5) = 750
2. 
   `y^(2)` - 5y - 750 = 0
3. (y + 25) (y - 30) = 0