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Let S = {4, 9, 14, 19, 24, 29}, E = {9, 19, 29}, F = {4, 14, 24}, and G = {24, 29}. (Enter ∅ for the empty set.) Find the event (E ∩ F ∩ G)c.

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Answer: Recall that E ∩ F ∩ G denotes the intersection of the three sets E, F, and G, and the superscript "c" denotes the complement of this set (i.e., everything outside of this intersection).

First, let's find E ∩ F ∩ G:

E ∩ F ∩ G = {24, 29}

Now, let's find the complement of this set:

(E ∩ F ∩ G)c = S - {24, 29}

This means that we take the set S and remove the elements 24 and 29.

So,

(E ∩ F ∩ G)c = {4, 9, 14, 19}

Explanation:

User Amadeu Antunes
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