Question

If x is the average of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m

Answer 1

Answer: To find the average of x, y, and z in terms of m, we first need to find expressions for x, y, and z in terms of m:

x = (m + 9)/2

y = (2m + 15)/2

z = (3m + 18)/3 = (m + 6)

To find the average of x, y, and z, we add them up and divide by the number of terms:

average = (x + y + z)/3

Substituting the expressions for x, y, and z, we get:

average = [(m + 9)/2 + (2m + 15)/2 + (m + 6)]/3

Simplifying the expression by combining like terms, we get:

average = (4m + 30)/6

Simplifying further by dividing both the numerator and denominator by 2, we get:

average = (2m + 15)/3

Therefore, the average of x, y, and z in terms of m is (2m + 15)/3.

Explanation: