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What is the perimeter for a rectangle diagonal of 29 feet and a width of 14 feet?

User Dunia
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Answer: We can use the Pythagorean theorem to find the length of the rectangle. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. In this case, the diagonal is the hypotenuse and the width and length of the rectangle are the other two sides.

Let's use "l" to represent the length of the rectangle:

l^2 + 14^2 = 29^2

l^2 = 29^2 - 14^2

l^2 = 561

l = sqrt(561)

l ≈ 23.67 feet

Now that we know the length and width of the rectangle, we can use the formula for the perimeter, which is the sum of all four sides:

Perimeter = 2 * length + 2 * width

Perimeter = 2 * 23.67 + 2 * 14

Perimeter = 47.34 + 28

Perimeter = 75.34 feet

Therefore, the perimeter of the rectangle is approximately 75.34 feet.

Explanation:

User TheRealVira
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