To calculate the amount of energy released when a 98g sample of water is cooled from 123°C to 23°C, we need to use the following formula:
Q = m * c * ΔT
Where:
Q = the amount of energy released or absorbed (in Joules)
m = the mass of the substance (in grams)
c = the specific heat capacity of the substance (in J/g°C)
ΔT = the change in temperature (in °C)
For water, the specific heat capacity is 4.18 J/g°C.
First, we need to calculate the change in temperature:
ΔT = 123°C - 23°C = 100°C
Next, we can plug in the values into the formula:
Q = 98g * 4.18 J/g°C * 100°C
Q = 40,964 J
Therefore, the amount of energy released when a 98g sample of water is cooled from 123°C to 23°C is 40,964 Joules