Question

What is the equation of the line that passes through the point (-3, 4) and has a
slope of 2/3?

Answer 1

Option #1: point-slope form: y - y1 = m ( x - x1 )

y - 4 = 2/3 ( x - (-3) ) or y - 4 = 2/3 ( x + 3 )

Option #2: slope-intercept form: y = mx + b

Take the point-slope and solve for y:

y - 4 = 2/3 ( x + 3 )

y - 4 = 2/3 x + 2

y = 2/3 x + 6

Answer 2

y = 2/3x + 6

Explanation:

The equation is y = mx + b

m = the slope

b = y-intercept

We know

m = 2/3

Y-intercept is located at (0, 6)

So, our equation is y = 2/3x + 6