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The graph of f ( x ) = − 1 /2 ( 1 /2 ) ^x − 3 + 5 is shifted downwards 5 units, and then shifted left 3 units, stretched vertically by a factor of 4 , and then reflected about the x -axis. a . What is the equation of the new function, g ( x ) ? g ( x ) = b . What is the y -intercept? ( , ) c . What is the domain? d . What is the range?

User Kyu
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Answer: a. To shift the graph downwards 5 units, we subtract 5 from the function, to shift it left 3 units, we add 3 to the input (the x-value), to stretch the graph vertically by a factor of 4, we multiply the function by 4, and to reflect it about the x-axis, we multiply the entire function by -1. Thus, the new function is:

g(x) = -4(1/2)^(x+3) - 5

b. To find the y-intercept, we set x=0 in the equation and solve for y:

g(0) = -4(1/2)^(0+3) - 5 = -9

Thus, the y-intercept is (0, -9).

c. The domain of the function g(x) is all real numbers, since there are no restrictions on the input x.

d. The range of the function g(x) is (-∞, -5], since the function is shifted downwards 5 units and stretched vertically by a factor of 4, which means that the maximum value of the function is -5, and it can take any value less than or equal to -5. The reflection about the x-axis does not change the range.

Explanation:

User Alan Wagner
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