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Miles per gallon of a vehicle is a random variable with a uniform distribution from 23

to 47. The probability that a random vehicle gets between 28 and 36 miles per gallon
is: Answer: (Round to four decimal places)

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Answer:

Explanation:

The range of the uniform distribution is from 23 to 47, so the minimum value (a) is 23 and the maximum value (b) is 47.

The probability density function for a uniform distribution is:

f(x) = 1 / (b - a) if a ≤ x ≤ b

= 0 otherwise

We want to find the probability that a random vehicle gets between 28 and 36 miles per gallon. This is the same as finding the area under the probability density function between x = 28 and x = 36.

Since the distribution is uniform, the probability density function is a horizontal line between x = 23 and x = 47, with height equal to 1 / (47 - 23) = 1/24.

The area under the probability density function between x = 28 and x = 36 is:

P(28 ≤ x ≤ 36) = (36 - 28) * 1/24 = 8/24 = 1/3

Therefore, the probability that a random vehicle gets between 28 and 36 miles per gallon is 1/3, or 0.3333 rounded to four decimal places.

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