Question

What’s the zeros of the function of f(x)=x^2+49

Answer 1

Explanation:

a zero of a function means what value of x causes a functional value of 0 ?

so,

0 = x² + 49

-49 = x²

x = ±sqrt(-49)

this tells us that there is no solution in real numbers, because no square of any real number can be negative.

but the function still has 2 zeroes. they are numbers of the set of imaginary or complex numbers.

that means they base on the square root of -1, called i.

x = ±sqrt(49×-1) = ±7×sqrt(-1) = ±7i

Answer 2

This function has no zeroes

Explanation:

To understand this problem we need to first understand what the zeroes of a function is; the zeroes of a function is the point at which the y value of a solution is equal to zero. So in this scenario all we need to do is plug 0 in for y:

`0 = x^2 +49`

Subtract 49 from both sides:

`-49 = x^2`

Now we can notice that
`x^2` is equal to -49; to our surprise there is no possible value for
`x^2` to be equal to a negative number. Therefore this function has no roots.