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9. If AFGH-AKJH, find FH.

F
G
x+8
4x-25
H
32
52
J
K

9. If AFGH-AKJH, find FH. F G x+8 4x-25 H 32 52 J K-example-1

1 Answer

1 vote

Answer:The required length of FH is obtained as 64.68.

What is the criteria for similarity of two triangles?

Two triangles are said to be similar when either the ratio of their corresponding sides are equal or all the corresponding angles are equal.

Two similar triangles are the same in shape but not in size.

The given diagram shows two similar triangles as ΔFGH and ΔKJH.

Since the ratios of the corresponding sides of the two triangles are equal, the following equation can be written for the given case as,

(x + 8)/32 = (4x - 25)/52

=> 52(x + 8) = 32(4x - 25)

=> 52x - 128x = -32 × 25 - 52 × 8

=> -76x = -1716

=> x = 22.42

Thus FH = 4x - 25 = 4 × 22.42 - 25 = 64.68

Hence, the length of FH for the given case is 64.68.

Explanation:

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