Question

14) If 3 moles of methane reacts with oxygen to produce carbon dioxide and water,

what mass of water is produced?

Answer 1

The balanced chemical equation for the combustion of methane (CH4) with oxygen (O2) is:

CH4 + 2O2 → CO2 + 2H2O

This equation tells us that for every mole of methane that reacts, we get 2 moles of water produced. So, for 3 moles of methane, we would get:

3 moles CH4 × (2 moles H2O / 1 mole CH4) = 6 moles H2O

Now we need to convert moles of water to mass. The molar mass of water (H2O) is 18.015 g/mol. So, the mass of water produced is:

6 moles H2O × 18.015 g/mol = 108.09 g

Therefore, if 3 moles of methane reacts with oxygen to produce carbon dioxide and water, 108.09 g of water is produced.

Step-by-step explanation: