Answer:
the balanced chemical equation for the reaction between aluminum (Al) and copper(II) sulfate (CuSO4) is:
2Al + 3CuSO4 → Al2(SO4)3 + 3Cu
This equation tells us that two moles of Al react with three moles of CuSO4 to produce one mole of Cu, and also produces one mole of Al2(SO4)3.
To determine the mass of Cu produced, we need to use the given masses of Al and CuSO4 to calculate how many moles of each reactant are present, and then use the mole ratios from the balanced equation to determine the moles of Cu produced. Finally, we can convert the moles of Cu to grams using its molar mass.
First, we calculate the moles of Al and CuSO4:
moles of Al = 1.08 g / 26.98 g/mol = 0.0400 mol
moles of CuSO4 = 9.58 g / 159.61 g/mol = 0.0600 mol
Next, we use the mole ratios from the balanced equation to determine the moles of Cu produced:
moles of Cu = (0.0400 mol Al) × (3 mol Cu / 2 mol Al) = 0.0600 mol Cu
Finally, we convert the moles of Cu to grams using its molar mass:
mass of Cu = 0.0600 mol × 63.55 g/mol = 3.81 g
Therefore, the total mass of Cu produced when 1.08 grams of Al reacts completely with 9.58 grams of CuSO4 is 3.81 grams.he balanced chemical equation for the reaction between aluminum (Al) and copper(II) sulfate (CuSO4) is:
2Al + 3CuSO4 → Al2(SO4)3 + 3Cu
This equation tells us that two moles of Al react with three moles of CuSO4 to produce one mole of Cu, and also produces one mole of Al2(SO4)3.
To determine the mass of Cu produced, we need to use the given masses of Al and CuSO4 to calculate how many moles of each reactant are present, and then use the mole ratios from the balanced equation to determine the moles of Cu produced. Finally, we can convert the moles of Cu to grams using its molar mass.
First, we calculate the moles of Al and CuSO4:
moles of Al = 1.08 g / 26.98 g/mol = 0.0400 mol
moles of CuSO4 = 9.58 g / 159.61 g/mol = 0.0600 mol
Next, we use the mole ratios from the balanced equation to determine the moles of Cu produced:
moles of Cu = (0.0400 mol Al) × (3 mol Cu / 2 mol Al) = 0.0600 mol Cu
Finally, we convert the moles of Cu to grams using its molar mass:
mass of Cu = 0.0600 mol × 63.55 g/mol = 3.81 g
Therefore, the total mass of Cu produced when 1.08 grams of Al reacts completely with 9.58 grams of CuSO4 is 3.81 grams.
Step-by-step explanation: