Answer:
255 grams of ammonia
Step-by-step explanation:
To solve this problem, we need to use the balanced chemical equation for the reaction between ammonia and water:
NH3 + H2O → NH4+ + OH-
From this equation, we can see that one molecule of ammonia reacts with one molecule of water to produce one hydroxide ion (OH-) and one ammonium ion (NH4+). Therefore, we need the same number of molecules of ammonia as water to form the products.
So, if we have 9.09X^23 molecules of water, we need the same number of molecules of ammonia:
9.09X^23 molecules of NH3
To calculate the mass of ammonia required, we need to use the molar mass of ammonia, which is approximately 17 g/mol:
1 mol of NH3 = 17 g
To convert the number of molecules of NH3 to grams, we need to use Avogadro's number:
1 mol = 6.022 × 10^23 molecules
Therefore, the mass of ammonia required is:
9.09X^23 molecules of NH3 * (1 mol/6.022 × 10^23 molecules) * 17 g/mol
= 2.55 × 10^2 g or 255 grams (rounded to two significant figures)
So, we need 255 grams of ammonia to form 9.09X^23 molecules of water.