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the length of a rectangle is 5 inches more than twice a number. The width is 4 inches less than the same number. If the area of the rectangle is 15, find the number

User Adjwilli
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1 Answer

6 votes

Answer: 5

Explanation:

A = Lw (area of rectangle is length times width)

A = 15 (Area is 15)

L = 2x + 5 (length is 2 times a number plus another 5)

w = x - 4 (width is 4 less than that number

Plug in the values:

15 = (2x + 5)(x - 4)

FOIL

15 = 2x2 - 8x + 5x - 20

simplify:

15 = 2x2 - 3x - 20

Subtract 15

0 = 2x2 - 3x - 35

Factor out the quadratic. We know that one number has to be 7 and the other 5 so that they multiply together to make 35, and that one of them has to be negative so that it's actually -35.

That means we have m * n = -35

We also need it set up so that so that 2m + n = -3:

2 * -5 + 7 = -3

0 = (2x + 7)(x - 5)

So:

0 = 2x + 7, or 0 = x - 5

x = -7/2 or 5

We cannot have a negative length, so x = 5

Check:

15 = (2 * 5 + 5) (5 - 4)

15 = 15 * 1

15 = 15

User Krishneil
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