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What is the mass of 7.93 * 10 ^ 32 molecules of NH3G (g) at STP?​

User Djoll
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1 Answer

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Answer:

This assumes that NH3G is supposed to be NH3.

1.31x10^9 grams of NH3 [Note comment in the Explanation section.]

Step-by-step explanation:

1) Determine the molar mass of NH3: 17.0 g/mole

2) Determine the moles of NH3:

1 mole NH3 = 6.02x10^23 molecules NH3 Use this as a conversion factor.

(7.93x10^32 molecules NH3)*((1 mole NH3)/(6.02x10^23 molecules NH3)

The molecules NH3 cancel and we're left with moles.

This is equal to 1.31x10^9 moles! [Was the exponent for the mass supposed to be 10^23 instead of 10^32?]

3) Determine the mass of 1.31x10^9 moles of NH3

(1.31x10^9 moles)*(17.0 g/mole) = 1.31x10^9 grams of NH3

[That is 2,888,055 pounds]

User Carleto
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