Question

50 pts.
Can someone help me with this. I cant figure it out

Answer 1

2

Explanation:

We use complex conjugates. A complex number multiplied by its conjugate creates a difference of squares pattern. In this scenario, 3-2i’s conjugate is 3+2i, because (3-2i)(3+2i)=9-(-4)=13. So how do we use conjugates to simplify this expression? We first multiply by
`(3+2i)/(3+2i)` to make the denominator real, while keeping the fraction the same, because the fraction we multiplied is 1.
our new fraction is (8-i)(3+2i)/13.

Expand the numerator: (26+13i)/13 = 2+i, so a is 2