Answer:
Starting with the given system of equations:
-3x + 3y = 4
-x + y = 3
To solve for y in terms of x, we can rearrange each equation to the slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
For the first equation, we can add 3x to both sides and divide by 3 to obtain:
3y = 3x + 4
y = x + 4/3
So the slope of the first equation is 1 and the y-intercept is 4/3.
For the second equation, we can add x to both sides to obtain:
y = x + 3
So the slope of the second equation is also 1, but the y-intercept is different at 3.
To determine the number of solutions, we can use either substitution or elimination.
Using substitution, we can solve for x in the second equation:
x = y - 3
Then substitute this expression for x in the first equation:
-3(y - 3) + 3y = 4
Simplifying, we get:
-3y + 9 + 3y = 4
9 = 4
This is a contradiction, so the system has no solution.
Alternatively, we can use elimination to solve for y:
-3x + 3y = 4
-x + y = 3
Multiplying the second equation by 3, we get:
-3x + 3y = 4
-3x + 3y = 9
Subtracting the second equation from the first, we get:
0x + 0y = -5
This is a contradiction, so the system has no solution.
In summary, the given system of equations has no solution. The two equations have the same slope but different y-intercepts.
Hope this helps you! I'm sorry if it's wrong. If you need more help, ask me! :]