Answer:
The reflected spot will appear to be closer than when the aquarium was empty.
N1 sin θ1 = N2 sin θ2 N1 is in air and equals 1, N2 is greater than one
θ2 is measured from the vertical and the ray is less than θ1
The distance to spot is less so it appears closer
(Consider a spot directly below the pointer L1 = N2 L2)
If N2 = 4/3 then L2 would be 3/4 L1