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Solve for vertex algebraically 3x^2+6x+7

User The Swine
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Hi Isabella Here’s your answer
To solve for the vertex of the equation 3x^2+6x+7 algebraically, we must first use the formula x=-b/(2a). In this equation, a is equal to 3, b is equal to 6, and c is equal to 7. Therefore, we can calculate the vertex by plugging in the values for a, b, and c into the formula. This gives us x=-6/(2*3), which simplifies to x=-1. Therefore, the vertex of the equation 3x^2+6x+7 is (-1, -2).
User Welsh
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