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find the equation of a straight line passing through a point (-2, 1) and perpendicular to the line -3x +5y +2=0​

User Per Salmi
by
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1 Answer

4 votes

Answer:

y= -5/3x - 7/3

Explanation:

1. solve the line

-3x +5y + 2 = 0

+3x +3x

5y + 2 = +3x

-2 -2

5y = +3x - 2

/5 /5

y= 3/5x -2/5

2. find slope

perpendicular lines have an opposite reciprocal slope to original line so your slope is now -5/3

3. find b ( y - intercept )

point ( -2 , 1 )

y - y1 = m ( x - x1 )

y - 1 = -5/3 ( x + 2 )

y -1 = -5/3x - 10/3

+1 + 1

y= -5/3x - 7/3