Okay, here we have this:
Considering the provided information we are going to calculate how many of each creature does she have, so we obtain the following:
• What bits of information are not explicitly stated in the problem that would help us figure out the answer? Do you need to look anything up or
pull some information from the back of your head?:
The missing information of the exercise is the amount of legs and eyes of each type of animal
• Which mathematical concept(s) that we've gone over so far would be helpful for solving this problem?:
The mathematical concept that we apply to solve this exercise will be the systems of equations of two equations by two incognites.
• Now, solve the problem and explain your solution. (It's OK if your answer isn't completely right. We're here to learn!):
According to the given information we obtain the following systems of equations:
8x+4y=104 (Equation of the legs)
8x+2y=80 (Eye equation)
"X" corresponds to the number of tarantulas and "y" to the number of frogs.
Solving:
We will clear x in the second equation:
8x+2y=80
8x=80-2y
x=(80-2y)/8
x=10-2y/8
Replacing in the first equation:
8x+4y=104
8(10-2y/8)+4y=104
80-2y+4y=104
80+2y=104
2y=24
y=24/2
y=12
Using this value of y in the equation of x:
x=10-2y/8
x=10-2(12)/8
x=10-24/8
x=10-3
x=7
Finally we obtain that she has 7 tarantulas and 12 frogs.