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One wall of a room measures 14 feet long and 8 feet

high. It contains a window 5 feet wide and 3.5 feet
high. The wall has an effective total R-value of 15.5.
Find the rate of heat flow through the wall when
the inside air temperature is 68 °F and the outside
temperature is 5 °F.

User Loaf
by
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1 Answer

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Answer: the rate of heat flow through the wall when the inside air temperature is 68 °F and the outside temperature is 5 °F is 257.42 BTU per hour.

Step-by-step explanation: The rate of heat flow through the wall can be found using the formula:

Rate of heat flow = (Temperature difference) / (Effective R-value)

The temperature difference is the difference between the inside and outside temperatures, which is:

Temperature difference = (68°F) - (5°F) = 63°F

The effective R-value of the wall is given as 15.5.

To calculate the total area of the wall, we first need to find the area of the window, which is:

Area of window = (width) x (height) = (5 ft) x (3.5 ft) = 17.5 square feet

The area of the wall without the window is:

Area of wall = (length) x (height) - Area of window

Area of wall = (14 ft) x (8 ft) - 17.5 square feet

Area of wall = 105.5 square feet

So, the rate of heat flow through the wall is:

Rate of heat flow = (Temperature difference) / (Effective R-value) x (Total area of the wall)

Rate of heat flow = (63°F) / (15.5) x (105.5 square feet)

Rate of heat flow = 257.42 BTU per hour

User Gadi Oron
by
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