The surface area of a right circular cylinder can be found by adding the area of the two circular bases and the lateral surface area.
The area of each circular base is πr^2, where r is the radius. In this case, the radius is 4 meters, so the area of each circular base is:
π(4)^2 = 16π
The lateral surface area is the area of the rectangle that forms the curved surface of the cylinder. The height of the rectangle is the same as the height of the cylinder, which is 8 meters, and the base of the rectangle is the circumference of the circle, which is 2πr. So, the lateral surface area is:
8(2πr) = 16πr
Substituting r = 4, we get:
16π(4) = 64π
Adding the areas of the two circular bases and the lateral surface area, we get:
16π + 16π + 64π = 96π
Using π = 3.14 and rounding to the nearest whole number, the surface area of the cylinder is:
96π ≈ 301 square meters