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Solve the system of equations.
−9y+4x−11=0
−3y+10x+31=0


User Vallie
by
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1 Answer

1 vote

Answer:

Multiplying the first equation by 3 and the second equation by 9, we get:

-27y + 12x - 33 = 0

-27y + 90x + 279 = 0

Now, we can subtract the first equation from the second to eliminate y:

-27y + 90x + 279 - (-27y + 12x - 33) = 0

78x + 312 = 0

78x = -312

x = -4

Substituting x = -4 into the first equation, we get:

-9y + 4(-4) - 11 = 0

-9y - 27 = 0

y = -3

Therefore, the solution to the system of equations is (x, y) = (-4, -3).

User Katzenhut
by
8.1k points