Question

Cl2 + 2NaBr → 2NaCl + Br2

How many moles of bromine gas, are produced by the reaction of chlorine gas and of 5.2 moles of sodium bromide, NaBr?

Answer 1

1 mole of Cl2 reacts with 2 moles of NaBr to produce 1 mole of Br2.

So, to calculate the number of moles of Br2 produced, we first need to find the number of moles of Cl2 required to react with 5.2 moles of NaBr. Since the stoichiometric ratio of Cl2 to NaBr is 1:2, we need half as many moles of Cl2 as moles of NaBr:

Number of moles of Cl2 = 5.2 moles NaBr / 2 = 2.6 moles Cl2

Now we can use the stoichiometric ratio between Cl2 and Br2 to calculate the number of moles of Br2 produced:

1 mole Cl2 produces 1 mole Br2

Therefore, 2.6 moles Cl2 will produce 2.6 moles Br2.

Step-by-step explanation: