Question

PLS HELP , in need to solve by using substitution and with checks

Answer 1

• (0, 2)

Explanation:

`\tt y=x+2\\3x+3y=6`

Substitute y= y=x+2 into 3x+3y=6

• 
  `\tt 3x+3(x+2)=6`

• 
  `\tt 6x+6=6`

Solve for x :-

• 
  `\tt 6x+6=6`

Cancel 6 from both sides:-

• 
  `\tt 6x=0`

Divide both sides by 6:-

• 
  `\tt \cfrac{6x}{6} =\cfrac{0}{6}`

• 
  `\boxed{\bf x=0}`

Now, Let's solve for y:-

Substitute x = 0 into y=x+2

• 
  `\tt y=0+2`

• 
  `\boxed{\bf y=2}`

Therefore, x = 0 and y = 2.

_________________

Check:-

To check a system of equations by substitution, we plug the values for x and y into the equations, If both simplified are true then your answer is correct.

Equation 1 :-

y = x + 2

• (2) = 0 + (2)

• 2=2 ✓

Equation 2 :-

3x+3y=6

• 3(0)+3(2)=6

• 0+6=6

• 6=6 ✓

__________________________

Hope this helps!