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alice wanted to buy 10 markers but was short of $5.20.Then she divided to buy 6 markers and used the remaining 4.40 to buy lunch. how much money did she have at first

User Chuck Hays
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3 votes
Let's use algebra to solve this problem. Let x be the amount of money Alice had at first.

If she wanted to buy 10 markers but was short of $5.20, it means the cost of 10 markers was x - 5.20.

Since she decided to buy only 6 markers, she spent 6/10 of the total cost, which is (6/10)*(x - 5.20) = 0.6x - 3.12.

She used the remaining $4.40 to buy lunch, so we can set up an equation:

0.6x - 3.12 + 4.40 = x

Simplifying this equation, we get:

0.4x = 7.52

x = 18.80

Therefore, Alice had $18.80 at first.
User Haseoh
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1 vote

Answer: k

Explanation:

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User JMichaelTX
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