Answer:
Let's denote the length, width, and
height of the cuboid as "l", "w", and
"h, respectively. Then, we have:
lw= 24 (Area of one face)
Ih 32 (Area of another face)
wh 48 (Area of the third face)
To solve for the dimensions of the
cuboid, we can use a system of
equations. We can start by solving
for one of the variables in terms of
the other two. For example, from the
first equation, we have:
W 24/
Substituting this into the second
equation, we get:
Ih 32
I(24/)h = 32
24h 32
h 32/24
h 4/3
Next, we can substitute the values of
h and w into the third equation to
solve for:
wh = 48
I(24/)(4/3) = 48
I2 72
= sqrt(72)
I= 6sqrt(2)
Finally, we can use the values of I
and w to solve for the remaining
dimension:
lw 24
(6sqrt(2))(24/(6sqrt(2))) = 24
W = 4sqrt(2)
Therefore, the lengths of the sides of
the cuboid are:
Length () = 6v2 cm
Width (w) = 4/2 cm
Height (h) = 4/3 cm