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A cuboid has faces with areas 24, 32, and 48 square centimeters. what are the lengths of its sides?

User Korrekorre
by
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1 Answer

4 votes

Answer:

Let's denote the length, width, and

height of the cuboid as "l", "w", and

"h, respectively. Then, we have:

lw= 24 (Area of one face)

Ih 32 (Area of another face)

wh 48 (Area of the third face)

To solve for the dimensions of the

cuboid, we can use a system of

equations. We can start by solving

for one of the variables in terms of

the other two. For example, from the

first equation, we have:

W 24/

Substituting this into the second

equation, we get:

Ih 32

I(24/)h = 32

24h 32

h 32/24

h 4/3

Next, we can substitute the values of

h and w into the third equation to

solve for:

wh = 48

I(24/)(4/3) = 48

I2 72

= sqrt(72)

I= 6sqrt(2)

Finally, we can use the values of I

and w to solve for the remaining

dimension:

lw 24

(6sqrt(2))(24/(6sqrt(2))) = 24

W = 4sqrt(2)

Therefore, the lengths of the sides of

the cuboid are:

Length () = 6v2 cm

Width (w) = 4/2 cm

Height (h) = 4/3 cm

User Hyperdrive
by
8.6k points

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