Answer
To calculate the mass fraction of CH3COOH in a 2M solution of 3 liters with a density of 0.981g/ml, we need to use the following steps:
Calculate the molarity of the solution:
Molarity (M) = moles of solute / liters of solution
Since we have a 2M solution of 3 liters, the moles of solute (CH3COOH) can be calculated as:
moles of solute = Molarity x liters of solution
= 2 x 3
= 6 moles of CH3COOH
So, we have 6 moles of CH3COOH in 3 liters of the solution.
Calculate the mass of the solution:
mass of solution = density x volume
= 0.981 g/ml x 3000 ml
= 2943 g
So, we have 2943 g of the solution.
Calculate the mass of CH3COOH in the solution:
mass of CH3COOH = moles of CH3COOH x molar mass of CH3COOH
= 6 x 60.05 g/mol
= 360.3 g
So, we have 360.3 g of CH3COOH in the solution.
Calculate the mass fraction of CH3COOH in the solution:
mass fraction of CH3COOH = mass of CH3COOH / mass of solution
= 360.3 g / 2943 g
= 0.1224 or 12.24%
Therefore, the mass fraction of CH3COOH in a 2M solution of 3 liters with a density of 0.981g/ml is 12.24%