Question

Write the quadratic equation y=x^2-6x-16

Answer 1

I’m assuming you want it in vertex form?

x=-b/2a and a=1, b=-6 and c=-16

So you have

x=-(-6)/2(1)= 6/2=3

So plug in x=3 for the equation and solve for y

y=(3)²-6(3)-16

y=9-18-16

y=-9-16

y=-25

So the vertex is (3,-25)

So the vertex is (h,k) where h=3 and k=-25

The vertex form is

y=a(x-h)²+k

so plugging in h=3 and k=-25 you get

y=[x-(3)]²+(-25)


Which is

y=(x-3)²-25

So the vertex form is

y=(x-3)²-25