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Work out the gradient of the line
3y-12x+7=0​

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Answer:

Explanation:

The gradient of the line 3y-12x+7=0 is; 4.

According to the question;

We are responsible to determine the gradient of the line 3y-12x+7=0.

To do this; we must rewrite the equation 3y-12x+7=0 in the slope-intercept form as follows;

3y-12x+7=0

3y = 12x - 7

y = 4x -7/4

By comparison with; y = mx + c;

where, gradient/slope is m;

The gradient/slope of the line 3y-12x+7=0 is; 4.

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