Answer:
Explanation:
The gradient of the line 3y-12x+7=0 is; 4.
According to the question;
We are responsible to determine the gradient of the line 3y-12x+7=0.
To do this; we must rewrite the equation 3y-12x+7=0 in the slope-intercept form as follows;
3y-12x+7=0
3y = 12x - 7
y = 4x -7/4
By comparison with; y = mx + c;
where, gradient/slope is m;
The gradient/slope of the line 3y-12x+7=0 is; 4.